Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems: 1-10

Answer

$W_{combined}=1991.43N$

Work Step by Step

First we find the mass of water: $m= (1000 \frac{kg}{m^3})*(0.2m^3)$ $m=200kg$ Then the total mass of the system is: $m_{total}=m_{plastic}+m_{water}=3kg+200kg=203kg$ And the weight of the combined system: $W_{combined}=m_{total}g=(203kg)*(9.81\frac{m}{s^2})$ $W_{combined}=1991.43N$
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