## Thermodynamics: An Engineering Approach 8th Edition

$W_{combined}=1991.43N$
First we find the mass of water: $m= (1000 \frac{kg}{m^3})*(0.2m^3)$ $m=200kg$ Then the total mass of the system is: $m_{total}=m_{plastic}+m_{water}=3kg+200kg=203kg$ And the weight of the combined system: $W_{combined}=m_{total}g=(203kg)*(9.81\frac{m}{s^2})$ $W_{combined}=1991.43N$