Answer
$1.1KN$
Work Step by Step
We can find the required tension as follows:
$T=m(g\frac{2gL(1-cos\theta)}{L})$
$\implies T=mg(1+2(1-cos\theta))$
We plug in the known values to obtain:
$T=(78)(9.81)(3-2cos37^{\circ})$
$T=110N=1.1KN$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.