Answer
$0.121m$
Work Step by Step
We can find the required distance as follows:
$d=\frac{v_i^2}{2g(sin\theta+\mu_kcos\theta)}$
We plug in the known values to obtain:
$d=\frac{(1.56)^2}{2(9.81)(sin 28.4^{\circ}+(0.62)cos 28.4^{\circ})}$
$d=0.121m$