Answer
$4cm$
Work Step by Step
We can find the required height as follows:
$h=\frac{1}{2g}(\frac{m_1+m_2}{m_1-m_2})v_i^2$
We plug in the known values to obtain:
$h=\frac{1}{2(9.81)}(\frac{3.7+4.1}{4.1-3.7})(0.20)^2$
$h=0.04m=4cm$
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