Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 6 - Applications of Newton's Laws - Problems and Conceptual Exercises - Page 182: 46

Answer

(a) downward (b) $0.92m/s^2$

Work Step by Step

(a) We know that $a=(\frac{m-Msin\theta}{m+M})g$ We plug in the known values to obtain: $a=(\frac{4.2-(5.7)sin35^{\circ}}{4.2+5.7})(9.81)$ $a=0.92m/s^2$ The positive sign shows that the direction of acceleration of the hanging block is downward. (b) As from part(a), we can see that the magnitude of acceleration is $0.92m/s^2$.
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