Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 6 - Applications of Newton's Laws - Problems and Conceptual Exercises - Page 181: 45

Answer

(a) upward (b) $0.076m/s^2$

Work Step by Step

(a) We know that $a=(\frac{m-Msin\theta}{m+M})g$ We plug in the known values to obtain: $a=(\frac{3.2-(5.7)sin35^{\circ}}{3.2+5.7})(9.81)$ $a=-0.076m/s^2$ The negative sign shows that the direction of acceleration of hanging block is upward. (b) From part (a), we can see that the magnitude of the hanging block's acceleration is $0.076m/s^2$.
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