Answer
(a) upward
(b) $0.076m/s^2$
Work Step by Step
(a) We know that
$a=(\frac{m-Msin\theta}{m+M})g$
We plug in the known values to obtain:
$a=(\frac{3.2-(5.7)sin35^{\circ}}{3.2+5.7})(9.81)$
$a=-0.076m/s^2$
The negative sign shows that the direction of acceleration of hanging block is upward.
(b) From part (a), we can see that the magnitude of the hanging block's acceleration is $0.076m/s^2$.