Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 27 - Optical Instruments - Problems and Conceptual Exercises - Page 971: 52

Answer

$11.7mm$

Work Step by Step

We know that $M=\frac{N}{f}$ We plug in the known values to obtain: $M=\frac{25.0cm}{10.1cm}=2.48$ Now we can find the apparent length as $apparent \space length=M\times actual \space length$ $apparent \space length=2.48\times 4.73=11.7mm$
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