Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 27 - Optical Instruments - Problems and Conceptual Exercises - Page 969: 5

Answer

(a) $2.58cm$ (b) $2.38cm$

Work Step by Step

(a) We can find the focal length of the eye as $f=(\frac{1}{d_i}-\frac{1}{d_\circ})^{-1}$ We plug in the known values to obtain: $f=(\frac{1}{2.60cm}-\frac{1}{285cm})^{-1}$ $f=2.58cm$ (b) As $f=(\frac{1}{d_i}-\frac{1}{d_\circ})^{-1}$ We plug in the known values to obtain: $f=(\frac{1}{2.60cm}-\frac{1}{28.5cm})^{-1}$ $f=2.38cm$
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