Answer
$14.3cm$
Work Step by Step
We can find the eye's nearest point distance as follows:
$d_{\circ}=(\frac{1}{f}-\frac{1}{d_i})^{-1}$
We plug in the known values to obtain:
$d_{\circ}=(\frac{1}{2.20}-\frac{1}{2.60})^{-1}$
$d_{\circ}=14.3cm$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 27 - Optical Instruments - Problems and Conceptual Exercises - Page 969: 4
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