Answer
$C). 8.06A$
Work Step by Step
We can find the required rms current as follows:
$X_c=\frac{1}{2\pi fC}$
$X_c=\frac{1}{2\pi(90\times 10^6)(1.50\times 10^{-12})}$
$X_c=1178.92\Omega$
and $X_L=2\pi fL=2\pi(90\times 10^6)(2.08\times 10^{-6})$
$X_L=1176.212\Omega$
$Z=\sqrt{R^2+(X_L-X_c)^2}$
We plug in the known values to obtain:
$Z=\sqrt{()^2+(1176.212-1178.92)^2}$
$Z=3.10\Omega$
Now $I_{rms}=\frac{V_{rms}}{Z}$
We plug in the known values to obtain:
$I_{rms}=\frac{25}{3.10}$
$I_{rms}=8.06A$
