Chapter 2 - One-Dimensional Kinematics - Problems and Conceptual Exercises - Page 50: 33

(a) $speed=3.8~m/s$ (b) $speed=9.9~m/s$

(a) We know that $v=v_{\circ}+a(t-t_{\circ})$ We plug in the known values to obtain: $v=0+(1.9m/s^2)(2.0s-0)$ $v=3.8m/s$ (b) As $v=v_{\circ}+a(t-t_{\circ})$ We plug in the known values to obtain: $v=0+(1.9m/s^2)(5.2s-0)$ $v=9.9m/s$