Answer
$a_{av}=2.20~m/s^{2}$
Work Step by Step
We can find the average acceleration as follows:
$a=\frac{\Delta v}{\Delta t}$
We plug in the known values to obtain:
$a=(\frac{173mi/h}{35.2s})(\frac{1h}{3600s})(\frac{1609m}{1mi})$
$a=2.20m/s^2$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 2 - One-Dimensional Kinematics - Problems and Conceptual Exercises - Page 50: 32
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