Answer
$1.50\times 10^2Hz$
Work Step by Step
We know that
$f^{\prime}=(\frac{1}{1-\frac{u}{v}})f$
We plug in the known values to obtain:
$f^{\prime}=(\frac{1}{1-\frac{31}{343}})(136)$
$f^{\prime}=1.50\times 10^2Hz$
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