Answer
$962N$
Work Step by Step
We can find the required force as follows:
$\tau=0$
$\implies -r_1F_T-r_2Mg+r_3F_B=0$
This can be rearranged as:
$F_T=\frac{-r_2Mg+r_3F_B}{r_1}$
We plug in the known values to obtain:
$F_T=\frac{-(0.1582m)(15.6N)+(0.3282m)(89N)}{0.0278m}$
$F_T=962N$
