Answer
$155.78N$
Work Step by Step
We know that
$\Sigma \tau=0$
$\implies r_1F_Q sin29^{\circ}-r_2mgcos39^{\circ}=0$
We plug in the known values to obtain:
$(0.12m)F_Q sin 29^{\circ}=(0.35m)mg cos 39^{\circ}$
This simplifies to:
$F_Q=155.78N$