Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 329: 92

$\Delta \theta=3.2 rev$

We know that $t=\sqrt{\frac{2y_{\circ}}{g}}$ We also know that $\Delta \theta=\omega_{avg}\Delta t$ $\implies \Delta \theta=\omega_{avg}\sqrt{\frac{2y_{\circ}}{g}}$ We plug in the known values to obtain: $\Delta \theta=12(\frac{1}{2\pi})\sqrt{\frac{2(14)}{9.18}}=3.2 rev$