Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 325: 33

(a) $v=0.38m/s$ (b) $v=0.24m/s$

(a) We know that $\omega=\frac{2\pi}{T}$ $\implies \omega=\frac{2\pi}{45}=0.14rad/s$ Now $v=r\omega$ We plug in the known values to obtain: $v=(2.75m)(0.14rad/s)$ $v=0.38m/s$ (b) The required linear speed is given as $v^{\prime}=r\omega$ We plug in the known values to obtain: $v^{\prime}=(1.75m)(0.14rad/s)$ $v^{\prime}=0.24m/s$