Physics: Principles with Applications (7th Edition)

Published by Pearson

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 255: 37

Answer

The max force the bicep muscle exerts on the forearm is about 1800N

Work Step by Step

We sum the torques about the elbow to solve for the force that the bicep muscle exerts on the forearm. Therefore; $(+ \circlearrowleft) \sum \tau=0$ $\sin105^{\circ}*F*.05m-2.0kg*9.8m/s^2*.15m-25kg*9.8m/s^2*.35m=0$ $F=(2.0kg*9.8m/s^2*.15m+25kg*9.8m/s^2*.35m)/(\sin105^{\circ}*0.05m)$ $F\approx1800N$ The max force the bicep muscle exerts on the forearm is about 1800N.

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