Answer
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Work Step by Step
From the statement of the problem, $F_{top,y}=F_{bottom,y}=0.5mg = 63.7 N$.
The forces on the door are due to gravity and due to the hinges. The net torque and the net force must be zero. Calculate torques about the bottom hinge. Let counterclockwise torques be positive. The top hinge is 1.50 m away from the bottom hinge.
$$\Sigma \tau = mg\frac{1.30m}{2}- F_{top,x}(1.5m)=0$$
$$ F_{top,x}=55.2 N$$
Because the net force on the door must also be zero in the horizontal direction, $ F_{bottom,x}=-55.2 N$.