Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - General Problems - Page 257: 64

Answer

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Work Step by Step

The maximum compressive force in a column is mg, and occurs at the bottom. For the column to buckle, its weight divided by the cross-sectional area equals the compressive strength CS of the material. The mass of the column is (density)(volume ). $$\frac{mg}{A}=CS=\frac{\rho hAg}{A}$$ $$h=\frac{CS}{\rho g}$$ a. For steel, using data from page 245: $$h=\frac{500\times10^6\;N/m^2}{7800\;kg/m^3 (9.80\;m/s^2)}=6500m$$ b. For granite, using data from page 245: $$h=\frac{170\times10^6\;N/m^2}{2700\;kg/m^3 (9.80\;m/s^2)}=6400m$$
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