Answer
The building does not topple.
Work Step by Step
Assume that the building is about to tip, so that all of the force on the building due to contact with the Earth is force $F_E$, as shown in the book’s figure. Calculate torques about that corner. Let counterclockwise torques be positive.
$$\Sigma \tau =F_A(90.0\;m)-mg(23.0\;m)$$
$$ =(950\;N/m^2)(180.0\;m)(76.0\;m)(90.0\;m)-(1.8\times10^7\;kg)(9.80\;m/s^2)(23.0\;m)=-2.9\times 10^9\;N\cdot m$$
This negative number represents a clockwise torque, meaning the torque due to gravity is greater than the torque due to the wind. The building would rotate back toward the ground, and not topple.
