Answer
$5.12 \frac{kg \cdot m^2}{s}$.
Work Step by Step
Find the angular momentum using equation 8–18.
$$L = I \omega = MR^2 \omega = (0.270 kg)(1.35m)^2(10.4 \frac{rad}{s})=5.12 \frac{kg \cdot m^2}{s}$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 8 - Rotational Motion - Problems - Page 225: 60
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