Answer
$1.36 \times 10^4 J$
Work Step by Step
The energy required equals the rotor’s final rotational kinetic energy.
The final rotational speed is 8750 rpm = 916.3 rad/s.
$$KE_{rot}=\frac{1}{2}I \omega^2 \approx 1.36 \times 10^4 J$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 8 - Rotational Motion - Problems - Page 225: 50
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