Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 7 - Linear Momentum - Problems - Page 193: 39

Answer

0.85 of the original kinetic energy was lost in the collision.

Work Step by Step

Let $M$ be the mass of each car. Original kinetic energy: $KE_0 = \frac{1}{2}(M)(38 ~m/s)^2$ $KE_0 = 720M ~J$ Kinetic energy after the collision: $KE_f = \frac{1}{2}(M)(15 ~m/s)^2$ $KE_f = 110M ~J$ The fraction of kinetic energy lost in the collision: $\frac{720M - 110M}{720M} = 0.85$ Therefore, 0.85 of the original kinetic energy was lost in the collision.
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