Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 7 - Linear Momentum - Problems - Page 193: 23

Answer

(a) $Impulse = 5~kg\cdot m/s$ (b) v = 80 m/s

Work Step by Step

(a) There are approximately 10 squares under the graph. We can use these 10 squares to find the impulse. Note that each square is $50 ~N \times 0.01~s$. $Impulse = (10)(50 ~N \times 0.01~s) = 5~kg\cdot m/s$ (b) $\Delta p = Impulse$ $m~\Delta v = Impulse$ $v = \frac{Impulse}{m} = \frac{5~kg\cdot m/s}{0.060~kg} = 80~m/s$
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