## Physics: Principles with Applications (7th Edition)

5.85 x $10^{7}$ N
Starting with Impulse-Momentum F$\Delta$t = $\Delta$(mv) We can divide both sides by the change in time F = $\Delta$(mv)/$\Delta$t In this problem, the velocity (v) is a constant 4.5 x $10^{4}$ m/s and the mass rate ($\Delta$m/$\Delta$t) is 1300 kg/s. From this, we can say that: F = v*$\Delta$m/$\Delta$t F = (4.5 x $10^{4}$ m/s)*(1300 kg/s) F = 5.85 x $10^{7}$ N