Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 7 - Linear Momentum - Problems: 18

Answer

The impulse given to the ball is $2.4~kg\cdot m/s$ in the horizontal direction away from the wall.

Work Step by Step

Note that only the horizontal component of velocity changes direction, so we only need to consider the horizontal change in momentum. $F\cdot t = \Delta p = m \Delta v$ $F\cdot t = (0.060~kg)(2)\times (28~m/s)~cos(45^{\circ})$ $F\cdot t = 2.4~kg\cdot m/s$ The impulse given to the ball is $2.4~kg\cdot m/s$ in the horizontal direction away from the wall.
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