Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - Problems - Page 167: 68

Answer

$2 \times 10^6 W$.

Work Step by Step

The work done on N skiers is the change in PE, N(mgh). Assume an average mass of 75 kg per skier. The power is the work done divided by time. $$P=\frac{W}{t}=\frac{Nmgh}{t}=\frac{47000(75 kg)(9.80\frac{m}{s^2})(200 m)}{3600s} \approx 2 \times 10^6 W $$
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