Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - Problems - Page 167: 63

Answer

$P = 2.9\times 10^4~W$ $P = 38~hp$

Work Step by Step

We can use the change in velocity to find the average acceleration: $a = \frac{\Delta v}{\Delta t} = \frac{(-30~km/h)(1000~m/km)(1~h/3600~s)}{7.0s} = -1.19~m/s^2$ Then, we use the magnitude of acceleration to find the average force opposing the car's motion: $F = ma = (1080~kg)(1.19~m/s^2) = 1285~N$ Next, we use the average force to find the power when the car is moving at a speed of 80 km/h: $P = F\cdot v$ $P = (1285~N)(80~km/h)(1000~m/km)(1~h/3600~s)$ $P = 2.9\times 10^4~W$ Since we want the car to travel at a constant speed, the car needs to provide the same magnitude of power: $P = 2.9\times 10^4~W$ $P = (2.9\times 10^4~W)(\frac{1~hp}{746~W}) = 38~hp$
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