Answer
332.5 J of thermal energy was generated in this process.
Work Step by Step
$PE = mgh$
$PE = (16.0 ~kg)(9.80 ~m/s^2)(2.20 ~m)$
$PE = 345 ~J$
$KE = \frac{1}{2}mv^2$
$KE = \frac{1}{2}(16.0 ~kg)(1.25 ~m/s)^2$
$KE = 12.5 ~J$
$Thermal ~Energy = PE - KE$
$Thermal ~Energy = 345 ~J - 12.5 ~J = 332.5 ~J$
332.5 J of thermal energy was generated in this process.
