Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - Problems: 6


$6.0 \times 10^3$ J.

Work Step by Step

The lawn’s area is 200 square meters, and the lawnmower’s width is 0.5 m. That means that the mower must be pushed a distance of (200/0.5) = 400 meters. The force and the displacement are both forward. The angle between them is 0 degrees. Use equation 6–1. $$W=(15 N)(400 m)(cos 0^{\circ}) = 6.0 \times 10^3 J$$
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