Answer
The minimum work is $1.0\times10^6$ joules.
Work Step by Step
The minimum work done by the applied force is equal to the change in potential energy, which is $mgh$.
We re-arrange the sin formula to make the subject:
$\frac{h}{d} = sin(\theta)$
$h = d\sin(\theta)$
Next, we substitute this formula in the formula for work below and solve:
$Work = mgh$
$Work = mgd\sin(\theta)$
$Work = (950 ~kg)(9.8 ~m/s^2)(710 ~m)(sin(9.0))$
$Work = 1.0\times10^6 ~joules$
The minimum work is $1.0\times10^6$ joules.
