Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - Problems - Page 134: 55

Answer

One revolution should take 9.6 seconds.

Work Step by Step

The formula: $\frac{v^2}{r} = a$ is re-arranged as: $v = \sqrt{ar}$ We can use this velocity to find the time for one revolution. $t = \frac{2\pi r}{v} = \frac{2 \pi r}{\sqrt{ar}} = 2\pi \sqrt{\frac{r}{a}} = 2\pi \sqrt{\frac{r}{0.70g}}$ $t = 2\pi \sqrt{\frac{16 ~m}{(0.70)(9.80 ~m/s^2)}} = 9.6 ~s$ Therefore, one revolution should take 9.6 seconds.
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