Answer
The person would experience a force of -19,000 N.
The distance traveled is 1.1 meters.
Work Step by Step
$a = 30g = (30)(9.80 ~m/s^2) = 294 ~m/s^2$
$F = ma = (65 ~kg)(-294 ~m/s^2) = -19,000 ~N$
The person would experience a force of -19,000 N.
Now, we find the distance traveled. The first step in this regard is to find the initial speed:
$v_0 = (95 ~km/h)(\frac{1000 ~m}{1 ~km})(\frac{1 ~h}{3600 ~s}) = 26 ~m/s$
We can use the initial velocity to find the distance traveled.
$x = \frac{v^2 - v_0^2}{2a} = \frac{0 - (26 ~m/s)^2}{(2)(-294 ~m/s^2)} = 1.1 ~m$
