Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 4 - Dynamics: Newton's Laws of Motion - Problems - Page 101: 12


$1.84 \frac{m}{s^{2}}$.

Work Step by Step

Choose up to be the positive direction. Newton’s second law tells us the required net force in the vertical direction. $$\Sigma F=F_t – mg = ma$$ $$a = \frac{ F_t-mg}{m} =\frac{163 N-(14.0 kg)(9.80 \frac{m}{s^{2}})}{14.0 kg} \approx 1.84 \frac{m}{s^{2}}$$ The answer is rounded to 3 significant figures. It is positive so the acceleration is upward. 163 N exceeds the weight, so the bucket is being lowered vertically, but slowing down.
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