Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 33 - Astrophysics and Cosmology - Search and Learn - Page 983: 7

Answer

a) -0.284 nm b) Blue shift c) $5.764\times10^{9}$ years

Work Step by Step

a) The speed of Andromeda Galaxy is small compared to the speed of light, so we use the formula $\Deltaλ=λ_{rest}(\frac{v}{c})$. Velocity of the galaxy is negative since it is approaching us. $$\Deltaλ=656nm(\frac{-130000m/s}{3\times 10^{8}m/s})=-0.284 nm$$ b) Since the galaxy is approaching and the wavelength has decreased, this is a blue shift. c) Assuming that their velocity remains the same, time can be calculated using the formula $t=(\frac{d}{v})$. $$t=\frac{2.5\times 10^{6} ly}{130000m/s}(\frac{9.46\times 10^{15}}{1 ly})(\frac{1 year}{3.156\times 10^{7}s})=5.764\times 10^{9} years$$
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