Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 33 - Astrophysics and Cosmology - Problems - Page 981: 9

Answer

See work below.

Work Step by Step

a. Density is mass divided by volume. $$\rho=\frac{M}{\frac{4}{3}\pi r^3}$$ $$ =\frac{1.99\times10^{30}kg}{\frac{4}{3}\pi (6.38\times10^{6}m)^3}$$ $$=1.83\times10^{9}kg/m^3$$ b. The volume is the same as that of the Earth, so the ratio of the densities is the ratio of the masses. $$\frac{\rho_{wd}}{\rho_E}=\frac{M_{wd}}{M_E}$$ $$=\frac{1.99\times10^{30}kg }{5.98\times10^{24}kg }=3.33\times10^5$$
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