Answer
$2.1\times10^8 ly$
Work Step by Step
Use equation 33–4, Hubble’s law.
$$v=H_od$$
$$d=\frac{v}{H_o}=\frac{(0.015)(3.00\times10^5km/s)}{21km/(s \cdot Mly)}=214Mly$$
$$=2.1\times10^8 ly $$
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