Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 33 - Astrophysics and Cosmology - General Problems - Page 982: 42

Answer

The distance to the nearest stars is 5.0 light-years.

Work Step by Step

$b = \frac{L}{4\pi d^2}$ $d = \sqrt{\frac{L}{4\pi b}}$ Let $d_2$ be the distance to the nearest stars and let $d_s$ be the distance to the sun. $\frac{d_2}{d_s} = \frac{\sqrt{\frac{L}{4\pi b_2}}}{\sqrt{\frac{L}{4\pi b_s}}} = \sqrt{\frac{b_s}{b_2}} = \sqrt{10^{11}}$ $d_2 = (\sqrt{10^{11}})(1.5\times 10^{11}~m)$ $d_2 = 4.74\times 10^{16}~m$ We can convert this distance to light-years. $d_2 = (4.74\times 10^{16}~m)(\frac{1~ly}{9.46\times 10^{15}~m})$ $d_2 = 5.0~ly$ The distance to the nearest stars is 5.0 light-years.
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