Answer
See the detailed answer below.
Work Step by Step
a) The daughter nucleus is given by
$$A(X)=191-0=\bf 191$$
$$Z(X)=76-(-1)=\bf 77$$
From Appendix B, we see that the daughter is
$$\rm \color{red}{\rm \bf ^{191}_{77}Ir}$$
b) We draw the energy-level of $\rm ^{191}_{76}Os$ and ${\rm ^{191}_{77}Ir}$ daughter with the excited states and the ground state, as we see the figure below.
c) The $\beta^-$ decay to the the higher excited state.
