Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 30 - Nuclear Physics and Radioactivity - General Problems - Page 883: 61

Answer

$2.6\times10^4 y$.

Work Step by Step

Once the tree dies, it doesn’t take in new carbon-14, which then decays. Calculate the age of the wooden tool using equation 30–4. and 30–7. $$N=N_0e^{-\lambda t}$$ Now apply equation 30-6, and the given information that the current number of C-14 atoms is only 4.5 percent of the number with which it started. $$N=N_0e^{-\lambda t}=N_0e^{-(ln2)t/(T_{1/2})}=0.045N_0$$ Solve for t. $$t=-\frac{ T_{1/2}ln(0.045)}{ln 2}=-\frac{(5730y)ln(0.045)}{ln2}=2.6\times10^4 y $$
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