Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 27 - Early Quantum Theory and Models of the Atom - General Problems - Page 801: 87

Answer

3.5 pm.

Work Step by Step

The theoretical limit of resolution is the wavelength of the electron. We find the wavelength from the momentum. To calculate the momentum, relate it to the kinetic energy and rest energy using the result cited on page 768 (Problem 26-45). $$\lambda=\frac{h}{p}=\frac{hc}{\sqrt{KE^2+2mc^2KE}}$$ The kinetic energy of the electron is 110 keV. $$\lambda=\frac{(6.626\times10^{-34}J\cdot s)(3.00\times10^8 m/s)}{(1.60\times10^{-19}J/eV)\sqrt{(110\times10^3 eV)^2+2(0.511\times10^6 eV) (110\times10^3 eV)}}$$ $$\lambda=3.5\times10^{-12} m$$ This is the theoretical limit of resolution for the electron microscope.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.