Answer
$v=0.436c=1.31\times10^8m/s$
Work Step by Step
Solve for the speed from the length contraction relationship, equation 26–3a.
$$\mathcal{l} = \mathcal{l}_{o} \sqrt{1-\frac{ v^{2} } { c^{2} }} $$
$$v=c\sqrt{1-(\frac{\mathcal{l}}{\mathcal{l}_o})^2}$$
$$v=c\sqrt{1-(\frac{0.900m}{1.00m})^2}$$
$$v=0.436c=1.31\times10^8m/s$$
