Answer
35 light years.
Work Step by Step
You measure the contracted length. Use equation 26–3a.
$$\mathcal{l} = \mathcal{l}_{o} \sqrt{1-\frac{ v^{2} } { c^{2} }} $$
$$= (135ly) \sqrt{1-\frac{ (2.90\times10^8m/s)^{2} } { (3.00\times10^8m/s)^{2} }} $$
$$= 34.6ly\approx 35ly$$
