Answer
$KE = 1.7\times10^{21}J$
20x greater
Work Step by Step
Use equation 26–5b to find the kinetic energy.
$$KE= (\gamma-1)mc^2$$
$$KE = (\frac{1}{\sqrt{1-0.90^2}}-1)(14500kg)(3.00\times10^8m/s)^2$$
$$KE = 1.7\times10^{21}J$$
The spaceship’s kinetic energy is about $2\times10^1$ times greater than the annual U.S. energy consumption.
