Answer
4.8 percent
Work Step by Step
Let the initial intensity be $I_o$.
The initial light is unpolarized, so the intensity after the first polarizer, $I_1$, will be half the initial intensity.
$$I_1=\frac{1}{2}I_o$$
Use equation 24–5 to relate the final intensity to $I_1$.
$$I_2=I_1cos^2\theta=\frac{1}{2}I_o cos^2\theta $$
$$\frac{I_2}{I_o}=\frac{cos^2\theta}{2}=\frac{cos^272^{\circ}}{2}$$
$$=0.048$$
