Answer
$0.20mm$
Work Step by Step
The first distance is L and the other distance is L+x. The path difference is $2(L+x)-2L=2x$
$2x_i=m_i\lambda$ and $2x_f=m_f\lambda$. $2x_f-2x_i=m_f\lambda-m_i\lambda$. $2d=N\lambda$
$d=\frac{N\lambda}{2}=0.20mm$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 24 - The Wave Nature of Light - Problems - Page 710: 56
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