Answer
$4.20\times10^{-7}m$
Work Step by Step
Use equation 22–4, $c=\lambda f$.
$$\lambda=\frac{c}{f}=\frac{3.00\times10^8m/s }{7.14\times10^{14}Hz}$$
$$\lambda=4.20\times10^{-7}m$$
This is visible light, on the violet end of the spectrum.
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