Answer
$1.1\times10^5\frac{V/m}{s}$
Work Step by Step
The electric field between the plates is given by equation 17–4a, E=V/d, where d is the spacing between the plates. Relate the rate of change of the electric field to that of the voltage.
$$E=\frac{V}{d}$$
$$\frac{\Delta E}{\Delta t}=\frac{1}{d}\frac{\Delta V}{\Delta t}$$
$$=\frac{1}{0.0011m}(120\frac{V}{s})=1.1\times10^5\frac{V/m}{s}$$
