Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 21 - Electromagnetic Induction and Faraday's Law - Problems - Page 621: 23

Answer

$f=16.5Hz$

Work Step by Step

$A_a=3.6\times10^{-3}m^2$ $A_w=\pi r^2=\pi(\frac{0.59\times10^{-3}}{2})=2.734\times10^{-7}m^2$ $l_w=4sN=4\times0.06\times85=20.4m$ $R_w=\frac{1.68\times10^{-8}\times20.4}{2.734\times10^{-7}}=1.254\Omega$ $I_{rms}=\frac{P}{V}=\frac{25.0W}{12.0V}=2.08A$ $V_c=V_{lightbulb}+V_{armature}=12V+(2.083A\times1.254\Omega)=14.61V$ $V_{rms}=\frac{E}{\sqrt{2}}=\frac{NBA_{armature}(2\pi f)}{\sqrt{2}}$ $f=16.5Hz$
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